我正在尝试通过我的 Spring 应用程序向我的 SQL 数据库添加(保存)一个“用户”(@GetMapping 请求当前有效)。我最近在我的物体类中添加了两个注释 @CreationTimeStamp 和 @UpdateTimeStamp...没有这两个注释的版本会产生与所示相同的错误。我正在使用 Postman 测验 API - 这是我的用户物体类:
@Table(name="users")
@Entity
public class Users {
@Id
@Column(name="email")
private String email;
@Temporal(TemporalType.TIMESTAMP)
@CreationTimestamp
@Column(name="created_at", updatable = false)
private Date createdAt;
@Column(name="description")
private String description;
@Column(name="followers_count")
private int followersCount;
@Column(name="friends_count")
private int friendsCount;
@Column(name="first_last_name")
private String firstLastName;
@Temporal(TemporalType.TIMESTAMP)
@UpdateTimestamp
@Column(name="login_at")
private Date loginAt;
@Column(name="password")
private String password;
@Column(name="username")
private String username;
@OneToMany(cascade=CascadeType.ALL,mappedBy="userOne")
List<Followers> followed;
@OneToMany(cascade=CascadeType.ALL,mappedBy="userTwo")
List<Followers> followers;
//auto generated getters and setters
}
我的 UsersDTO 类
public class UsersDTO {
@Email
@NotNull
private String email;
@PastOrPresent
private Date createdAt;
@Size(min=0,max=44)
private String description;
@NotNull
private int followersCount;
@NotNull
private int friendsCount;
@Pattern(regexp="/^[a-z ,.'-] $/i")
private String firstLastName;
@PastOrPresent
private Date loginAt;
@NotNull
private String password;
@NotNull
private String username;
//auto gen getters and setters
}
我的用户ServiceImpl
@Service
@Transactional
public class UsersServiceImpl implements UsersService{
@Autowired
private UsersRepository userRepo;
@Override
public List<Users> getAll() throws SubException {
return (List<Users>) userRepo.findAll();
}
@Override
public UsersDTO findByUsersEmail(String email) throws SubException {
UsersDTO userDTO = null;
Users user = userRepo.findById(email.toLowerCase()).orElseThrow(()->new SubException("General.EXCEPTION_MESSAGE"));
userDTO = new UsersDTO();
userDTO.setEmail(user.getEmail());
userDTO.setCreatedAt(user.getCreatedAt());
userDTO.setDescription(user.getDescription());
userDTO.setFollowersCount(user.getFollowersCount());
userDTO.setFriendsCount(user.getFriendsCount());
userDTO.setFirstLastName(user.getFirstLastName());
userDTO.setLoginAt(user.getLoginAt());
userDTO.setPassword(user.getPassword());
userDTO.setUsername(user.getUsername());
return userDTO;
}
@Override
public String addUser(UsersDTO userDTO) throws SubException {
boolean emailAvail = userRepo.findById(userDTO.getEmail().toLowerCase()).isEmpty();
String emailAdded = null;
if(emailAvail) {
Users user = new Users();
user.setEmail(userDTO.getEmail().toLowerCase());
user.setCreatedAt(userDTO.getCreatedAt());
user.setDescription(userDTO.getDescription());
user.setFollowersCount(userDTO.getFollowersCount());
user.setFriendsCount(userDTO.getFriendsCount());
user.setFirstLastName(userDTO.getFirstLastName());
user.setLoginAt(userDTO.getLoginAt());
String hashedpwd = null;
try {
hashedpwd = HashingUtility.getHashValue(userDTO.getPassword());
} catch (NoSuchAlgorithmException e) {}
user.setPassword(hashedpwd);
user.setUsername(userDTO.getUsername());
userRepo.save(user);
emailAdded = user.getEmail().toLowerCase();
}
return emailAdded;
}
}
我的 UsersAPI 类
@RestController
@RequestMapping("users")
@Validated
@CrossOrigin
public class UsersAPI {
@Autowired
Environment env;
@Autowired
private UsersServiceImpl userService;
@GetMapping("/{email}")
ResponseEntity<UsersDTO> findByUsersEmail(@PathVariable String email) throws SubException{
return new ResponseEntity<UsersDTO>(userService.findByUsersEmail(email), HttpStatus.OK);
}
@GetMapping("/all")
ResponseEntity<List<Users>> getAll() throws SubException{
return new ResponseEntity<List<Users>>(userService.getAll(),HttpStatus.OK);
}
@PostMapping("/add")
ResponseEntity<String> addUser(@Valid @RequestBody UsersDTO userDTO) throws SubException {
return new ResponseEntity<String>(userService.addUser(userDTO),HttpStatus.CREATED);
}
}
每当我尝试通过 Postman 添加用户时,都会出现此错误(我包括了休眠行):
Hibernate: select users0_.email as email1_0_0_, users0_.created_at as created_2_0_0_, users0_.description as descript3_0_0_, users0_.first_last_name as first_la4_0_0_, users0_.followers_count as follower5_0_0_, users0_.friends_count as friends_6_0_0_, users0_.login_at as login_at7_0_0_, users0_.password as password8_0_0_, users0_.username as username9_0_0_ from users users0_ where users0_.email=?
Hibernate: select users0_.email as email1_0_1_, users0_.created_at as created_2_0_1_, users0_.description as descript3_0_1_, users0_.first_last_name as first_la4_0_1_, users0_.followers_count as follower5_0_1_, users0_.friends_count as friends_6_0_1_, users0_.login_at as login_at7_0_1_, users0_.password as password8_0_1_, users0_.username as username9_0_1_, followed1_.users_email as users_em2_1_3_, followed1_.followers_email as follower1_1_3_, followed1_.followers_email as follower1_1_0_, followed1_.users_email as users_em2_1_0_ from users users0_ left outer join users_has_followers followed1_ on users0_.email=followed1_.users_email where users0_.email=?
Hibernate: insert into users (created_at, description, first_last_name, followers_count, friends_count, login_at, password, username, email) values (?, ?, ?, ?, ?, ?, ?, ?, ?)
2022-01-10 11:33:43.019 WARN 1468 --- [nio-3333-exec-1] o.h.engine.jdbc.spi.SqlExceptionHelper : SQL Error: 1048, SQLState: 23000
2022-01-10 11:33:43.019 ERROR 1468 --- [nio-3333-exec-1] o.h.engine.jdbc.spi.SqlExceptionHelper : Column 'first_last_name' cannot be null
2022-01-10 11:33:43.020 INFO 1468 --- [nio-3333-exec-1] o.h.e.j.b.internal.AbstractBatchImpl : HHH000010: On release of batch it still contained JDBC statements
2022-01-10 11:33:43.030 ERROR 1468 --- [nio-3333-exec-1] o.a.c.c.C.[.[.[/].[dispatcherServlet] : Servlet.service() for servlet [dispatcherServlet] in context with path [] threw exception [Request processing failed; nested exception is org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement] with root cause
java.sql.SQLIntegrityConstraintViolationException: Column 'first_last_name' cannot be null
这是我输入 Postman 的 JSON 正文(Body -> raw 和 JSON 被选为选项):
{
"email": "testemail@gmail.com",
"created_at": "2022-01-09 11:11:11",
"description": "added through rest api",
"followers_count": 0,
"friends_count": 0,
"first_last_name": "Tester Testingson",
"login_at": "2022-01-09 11:11:11",
"password": "hunter2",
"username": "ttestingson2"
}
邮递员给出了这个错误:
"timestamp": "2022-01-10T17:37:52.275 00:00",
"status": 500,
"error": "Internal Server Error",
"trace": "org.springframework.dao.DataIntegrityViolationException: could not execute statement; SQL [n/a]; constraint [null]; nested exception is org.hibernate.exception.ConstraintViolationException: could not execute statement
我可以在 MySQL Shell 中手动添加用户:
insert into users (email,created_at,description,followers_count,friends_count,first_last_name,login_at,password,username) values ('testemail@gmail.com','2022-01-09 11:11:11', 'added through rest api',0,0,'Tester Testingson', '2022-01-09 11:11:11', 'hunter2', 'ttestingson2');
我的追随者物体中确实有一个@EmbdeddId,但我认为这不会影响我添加用户。
@Entity
@Table(name="users_has_followers")
public class Followers {
@EmbeddedId
private FollowersId followers;
@ManyToOne
@MapsId("users_email")
@JoinColumn(name="users_email")
Users userOne;
@ManyToOne
@MapsId("followers_email")
@JoinColumn(name="followers_email")
Users userTwo;
}
和@Embeddable 类
@Embeddable
public class FollowersId implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
private String users_email;
private String followers_email;
public String getUsers_email() {
return users_email;
}
public void setUsers_email(String users_email) {
this.users_email = users_email;
}
public String getFollowers_email() {
return followers_email;
}
public void setFollowers_email(String followers_email) {
this.followers_email = followers_email;
}
}
这是我的数据库 UML 图:https : //drive.google.com/file/d/1xljVZVRvEMGkKVULBi-Suqn1RFO_b7b7/view?usp=sharing
这是 SQL 脚本:
-- MySQL Script generated by MySQL Workbench
-- Mon Jan 10 15:14:53 2022
-- Model: New Model Version: 1.0
-- MySQL Workbench Forward Engineering
SET @OLD_UNIQUE_CHECKS=@@UNIQUE_CHECKS, UNIQUE_CHECKS=0;
SET @OLD_FOREIGN_KEY_CHECKS=@@FOREIGN_KEY_CHECKS, FOREIGN_KEY_CHECKS=0;
SET @OLD_SQL_MODE=@@SQL_MODE, SQL_MODE='ONLY_FULL_GROUP_BY,STRICT_TRANS_TABLES,NO_ZERO_IN_DATE,NO_ZERO_DATE,ERROR_FOR_DIVISION_BY_ZERO,NO_ENGINE_SUBSTITUTION';
-- -----------------------------------------------------
-- Schema java_subscription_app
-- -----------------------------------------------------
-- -----------------------------------------------------
-- Schema java_subscription_app
-- -----------------------------------------------------
CREATE SCHEMA IF NOT EXISTS `java_subscription_app` DEFAULT CHARACTER SET utf8 ;
USE `java_subscription_app` ;
-- -----------------------------------------------------
-- Table `java_subscription_app`.`users`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `java_subscription_app`.`users` (
`email` VARCHAR(45) NOT NULL,
`created_at` DATETIME NOT NULL,
`description` VARCHAR(45) NULL,
`followers_count` INT NOT NULL,
`friends_count` INT NOT NULL,
`first_last_name` VARCHAR(45) NOT NULL,
`login_at` TIMESTAMP NOT NULL,
`password` VARCHAR(45) NOT NULL,
`username` VARCHAR(45) NOT NULL,
PRIMARY KEY (`email`))
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `java_subscription_app`.`posts`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `java_subscription_app`.`posts` (
`id` INT NOT NULL AUTO_INCREMENT,
`created_at` DATETIME NOT NULL,
`like_count` INT NOT NULL,
`liked` TINYINT NOT NULL,
`text` VARCHAR(100) NULL,
`users_email` VARCHAR(45) NOT NULL,
PRIMARY KEY (`id`),
INDEX `fk_posts_users1_idx` (`users_email` ASC) VISIBLE,
CONSTRAINT `fk_posts_users1`
FOREIGN KEY (`users_email`)
REFERENCES `java_subscription_app`.`users` (`email`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `java_subscription_app`.`comments`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `java_subscription_app`.`comments` (
`id` INT NOT NULL AUTO_INCREMENT,
`message` VARCHAR(100) NULL,
`created_at` DATETIME NOT NULL,
`posts_id` INT NOT NULL,
PRIMARY KEY (`id`),
INDEX `fk_comments_posts1_idx` (`posts_id` ASC) VISIBLE,
CONSTRAINT `fk_comments_posts1`
FOREIGN KEY (`posts_id`)
REFERENCES `java_subscription_app`.`posts` (`id`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `java_subscription_app`.`payment`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `java_subscription_app`.`payment` (
`id` INT NOT NULL AUTO_INCREMENT,
`expire_date` DATE NOT NULL,
`name_on_card` VARCHAR(45) NOT NULL,
`number` VARCHAR(45) NOT NULL,
`security_code` INT NOT NULL,
`users_email` VARCHAR(45) NOT NULL,
PRIMARY KEY (`id`),
INDEX `fk_payment_users1_idx` (`users_email` ASC) VISIBLE,
CONSTRAINT `fk_payment_users1`
FOREIGN KEY (`users_email`)
REFERENCES `java_subscription_app`.`users` (`email`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
-- -----------------------------------------------------
-- Table `java_subscription_app`.`users_has_followers`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `java_subscription_app`.`users_has_followers` (
`users_email` VARCHAR(45) NOT NULL,
`followers_email` VARCHAR(45) NOT NULL,
INDEX `fk_users_has_users_users2_idx` (`followers_email` ASC) VISIBLE,
INDEX `fk_users_has_users_users1_idx` (`users_email` ASC) VISIBLE,
PRIMARY KEY (`followers_email`, `users_email`),
CONSTRAINT `fk_users_has_users_users1`
FOREIGN KEY (`users_email`)
REFERENCES `java_subscription_app`.`users` (`email`)
ON DELETE NO ACTION
ON UPDATE NO ACTION,
CONSTRAINT `fk_users_has_users_users2`
FOREIGN KEY (`followers_email`)
REFERENCES `java_subscription_app`.`users` (`email`)
ON DELETE NO ACTION
ON UPDATE NO ACTION)
ENGINE = InnoDB;
USE `java_subscription_app` ;
-- -----------------------------------------------------
-- Placeholder table for view `java_subscription_app`.`view1`
-- -----------------------------------------------------
CREATE TABLE IF NOT EXISTS `java_subscription_app`.`view1` (`id` INT);
-- -----------------------------------------------------
-- View `java_subscription_app`.`view1`
-- -----------------------------------------------------
DROP TABLE IF EXISTS `java_subscription_app`.`view1`;
USE `java_subscription_app`;
SET SQL_MODE=@OLD_SQL_MODE;
SET FOREIGN_KEY_CHECKS=@OLD_FOREIGN_KEY_CHECKS;
SET UNIQUE_CHECKS=@OLD_UNIQUE_CHECKS;
我不确定是什么导致了我的问题...请帮助!谢谢
uj5u.com热心网友回复:
首先保持一种代码风格сamelCase 或snake_case。您发送“first_last_name”,但需要“firstLastName”。不需要发送栏位login_at,created_at你已经放了适当的注释。
{
"email": "testemail@gmail.com",
"description": "added through rest api",
"followersCount": 0,
"friendsCount": 0,
"firstLastName": "Tester Testingson",
"password": "hunter2",
"username": "ttestingson2"
}
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